Hess's Law & Energy Cycles
Enthalpy change depends only on where you start and finish — not the route. Build an energy cycle and calculate ΔH the indirect way. Hess's law, made visual.
Some enthalpy changes are almost impossible to measure directly — you can’t easily watch carbon turn straight into a particular compound in a calorimeter. Hess’s law lets you calculate them anyway, by taking the scenic route.
Why the route doesn’t matter
Enthalpy is a state function: its value depends only on the current state of a system, not on how the system arrived there. So the enthalpy changeof a reaction, ΔH, depends only on the enthalpies of the starting materials and the products — the start and end states, and nothing about the path between them.
That is Hess’s law: the total enthalpy change for a reaction is the same whatever route is taken from reactants to products. It follows directly from the conservation of energy — if two routes gave different values you could cycle around them and create energy from nothing.
Walk or drive between two towns and the change in altitude is identical — the road you choose can’t change the height difference.
See it: the enthalpy profile
A reaction-coordinate diagram plots enthalpy as the reaction proceeds. The reactants start at one level, climb over an activation-energy hump, and settle at the product level. The vertical gap between start and finish is ΔH.
Toggle between an exothermic and an endothermic reaction below, and notice that adding a catalyst lowers the hump but never moves the two end levels — so ΔH is left completely untouched.
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A reaction-coordinate (enthalpy) diagram. The enthalpy change ΔH is the difference between the product and reactant energy levels — negative for exothermic (products lower) and positive for endothermic (products higher). Because enthalpy is a state function, ΔH depends only on these levels, not on the route, which is the basis of Hess’s law.
Building an energy cycle
The practical trick is to draw an energy cycle: a triangle linking the reaction you want to reactions whose ΔH you already know. The most common known values are enthalpies of formation (forming one mole of a compound from its elements) and enthalpies of combustion (burning a substance completely in oxygen).
You put your target reaction along the top of the cycle, then follow an alternative routedown through the known reactions. Because Hess’s law guarantees both routes give the same total, you just add the ΔH values along the indirect path — reversing the sign of any step you have to travel backwards against its arrow.
A worked calculation
When every known value is an enthalpy of formation, the whole cycle collapses into one tidy formula:
ΔH = ΣΔHf(products) − ΣΔHf(reactants)
Find ΔH for the combustion of methane, CH₄ + 2O₂ → CO₂ + 2H₂O, given these standard enthalpies of formation (all in kJ/mol): ΔHf(CH₄) = −75, ΔHf(CO₂) = −394, ΔHf(H₂O) = −286. The element O₂ has ΔHf = 0 by definition.
Apply ΔH = ΣΔHf(products) − ΣΔHf(reactants), being careful to multiply each value by the number of moles in the balanced equation:
products = (−394) + 2×(−286) = −966 kJ; reactants = (−75) + 2×0 = −75 kJ.
So ΔH = (−966) − (−75) = −891 kJ/mol. The negative sign confirms the combustion is exothermic, as expected.
Common mistakes
Practice
Forming one mole of a compound from its elements releases 400 kJ, so its enthalpy of formation is −400 kJ/mol. What is ΔH for decomposing one mole of that compound back into its elements?
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+400 kJ/mol.Decomposition is the exact reverse of formation, so the magnitude is unchanged but the sign flips — a reaction that released 400 kJ must absorb 400 kJ to run backwards.
Where next?
The same cycle-building logic scales up to Born–Haber cyclesfor ionic compounds, where lattice enthalpies that can never be measured directly are found entirely by Hess’s law.
Frequently asked questions
What is Hess's law?+
Why is enthalpy a state function?+
How do you use Hess's law to find ΔH?+
What is the difference between exothermic and endothermic?+
The ScholarsGate Chemistry Team
Oxbridge & Russell Group chemistry tutors
Written and reviewed by ScholarsGate tutors who teach A-Level and undergraduate chemistry. Every explainer is checked against the AQA, Edexcel, OCR and CIE specifications.
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